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You are given two vectors in a 2D coordinate system: vector A with components (-3, 4) and vector B with components (5, -2). Calculate the angle between vectors A and B.

Question

You are given two vectors in a 2D coordinate system: vector A with components (-3, 4) and vector B with components (5, -2). Calculate the angle between vectors A and B.

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Solution 1

Sure, here are the steps to calculate the angle between two vectors:

  1. First, we need to calculate the dot product of the two vectors. The dot product of two vectors A and B is given by A.B = AxBx + AyBy. So, for vectors A(-3, 4) and B(5, -2), the dot product is (-35) + (4-2) = -15 - 8 = -23.

  2. Next, we calculate the magnitude (or length) of each vector. The magnitude of a vector A(Ax, Ay) is given by sqrt(Ax^2 + Ay^2). So, the magnitude of vector A is sqrt((-3)^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5. Similarly, the magnitude of vector B is sqrt((5)^2 + (-2)^2) = sqrt(25 + 4) = sqrt(29).

  3. Now, we can calculate the cosine of the angle between the two vectors using the formula cos(theta) = A.B / (||A|| ||B||), where A.B is the dot product of A and B, and ||A|| and ||B|| are the magnitudes of A and B respectively. Substituting the values we calculated, we get cos(theta) = -23 / (5 * sqrt(29)).

  4. To find the angle theta, we take the arccosine (inverse cosine) of the value we calculated. Make sure your calculator is in degree mode if you want the angle in degrees. So, theta = arccos(-23 / (5 * sqrt(29))).

  5. The result will be the angle between the two vectors in degrees.

This problem has been solved

Solution 2

Sure, here are the steps to calculate the angle between two vectors:

Step 1: Calculate the dot product of the two vectors. The dot product of two vectors A and B is given by A.B = a1b1 + a2b2. In this case, A.B = (-35) + (4-2) = -15 - 8 = -23.

Step 2: Calculate the magnitude of each vector. The magnitude of a vector A with components (a1, a2) is given by |A| = sqrt(a1^2 + a2^2). So, |A| = sqrt((-3)^2 + 4^2) = 5 and |B| = sqrt((5)^2 + (-2)^2) = sqrt(29).

Step 3: Use the dot product and magnitudes to calculate the cosine of the angle between the vectors. The cosine of the angle θ is given by cos(θ) = A.B / (|A||B|). So, cos(θ) = -23 / (5sqrt(29)) = -23/sqrt(725).

Step 4: Use the arccos function to find the angle θ. θ = arccos(-23/sqrt(725)).

Please note that the arccos function will give the angle in radians. To convert to degrees, multiply by 180/π.

This problem has been solved

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