The valid host range of the subnet 192.168.2.128/27 is 192.168.2.129 - 192.168.2.158.

Here's how you calculate it:

1. The /27 means that the first 27 bits of the IP address are used for the network address and the remaining 5 bits are used for host addresses.

2. The 27th bit is in the fourth octet, which is divided into 32 blocks (2^5 = 32).

3. The subnet 192.168.2.128/27 falls into the fifth block, which ranges from 192.168.2.128 to 192.168.2.159.

4. The first address of a block (192.168.2.128 in this case) is the network address and the last address (192.168.2.159) is the broadcast address.

5. Therefore, the valid host range is from the second address to the second last address in the block, which is 192.168.2.129 to 192.168.2.158.

Question

The valid host range of the subnet 192.168.2.128/27 is 192.168.2.129 - 192.168.2.158.

Here's how you calculate it:

1. The /27 means that the first 27 bits of the IP address are used for the network address and the remaining 5 bits are used for host addresses.

2. The 27th bit is in the fourth octet, which is divided into 32 blocks (2^5 = 32).

3. The subnet 192.168.2.128/27 falls into the fifth block, which ranges from 192.168.2.128 to 192.168.2.159.

4. The first address of a block (192.168.2.128 in this case) is the network address and the last address (192.168.2.159) is the broadcast address.

5. Therefore, the valid host range is from the second address to the second last address in the block, which is 192.168.2.129 to 192.168.2.158.

Knowee AI · Accepted Answer

The valid host range of the subnet 192.168.2.128/27 is 192.168.2.129 - 192.168.2.158.

Here's how you calculate it:

1. The /27 means that the first 27 bits of the IP address are used for the network address and the remaining 5 bits are used for host addresses.

2. The 27th bit is in the fourth octet, which is divided into 32 blocks (2^5 = 32).

3. The subnet 192.168.2.128/27 falls into the fifth block, which ranges from 192.168.2.128 to 192.168.2.159.

4. The first address of a block (192.168.2.128 in this case) is the network address and the last address (192.168.2.159) is the broadcast address.

5. Therefore, the valid host range is from the second address to the second last address in the block, which is 192.168.2.129 to 192.168.2.158.

What is the valid host range of the subnet 192.168.2.128/27?Question 7Select one:192.168.2.129 - 192.168.2.142192.168.2.128 - 192.168.2.255192.168.2.128 - 192.168.2.135192.168.2.129 - 192.168.2.158