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class Solution: def longestCommonPrefix(self, v: List[str]) -> str: ans="" v=sorted(v) first=v[0] last=v[-1] for i in range(min(len(first),len(last))): if(first[i]!=last[i]): return ans ans+=first[i] return ans

Question

class Solution: def longestCommonPrefix(self, v: List[str]) -> str: ans="" v=sorted(v) first=v[0] last=v[-1] for i in range(min(len(first),len(last))): if(first[i]!=last[i]): return ans ans+=first[i] return ans

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Solution 1

This is a Python code snippet for a function named longestCommonPrefix in a class named Solution. The function takes a list of strings as an argument and returns the longest common prefix of the strings in the list. Here's a step-by-step explanation of the code:

  1. The function longestCommonPrefix is defined with one parameter v, which is a list of strings.

  2. An empty string ans is initialized to store the longest common prefix.

  3. The list v is sorted in lexicographical order. This is done because the longest common prefix of all strings will be the longest common prefix of the first and last string in the sorted list.

  4. The first string in the sorted list is stored in the variable first and the last string is stored in the variable last.

  5. A for loop is run for the minimum length of first and last. This is done because the common prefix can't be longer than the shortest string.

  6. Inside the loop, if the characters at the ith index of first and last are not the same, the function returns ans because no further common prefix is possible.

  7. If the characters are the same, the character is added to ans.

  8. After the loop, ans is returned which contains the longest common prefix of the strings in the list.

This function uses the vertical scanning approach where the characters at the same index of the strings are compared one by one.

This problem has been solved

Solution 2

This is a Python code for finding the longest common prefix in a list of strings. Here's a step-by-step explanation:

  1. The class Solution is defined with a method longestCommonPrefix(self, v: List[str]) -> str:. This method takes a list of strings v as input and returns a string.

  2. An empty string ans is initialized to store the longest common prefix.

  3. The list v is sorted in lexicographical order. This is done because the longest common prefix of the list will be the longest common prefix of the first and last string in the sorted list.

  4. The first string first and the last string last in the sorted list are stored in variables.

  5. A for loop is run for the minimum length of first and last. This is done because the common prefix can't be longer than the shortest string.

  6. Inside the loop, if the characters at the ith index of first and last are not the same, the function returns ans as the longest common prefix found till now.

  7. If the characters are the same, the character is added to ans.

  8. After the loop ends, ans is returned which contains the longest common prefix of the list of strings.

This code uses the concept of sorting and string comparison to find the longest common prefix.

This problem has been solved

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