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6. What are the values of these sums, where S = {1, 3, 5, 7}?a)1j Sj j    b)2j Sj c)2j S7. What are the values of the following products?a)100ii b) 10011 ii c)40!ii

Question

  1. What are the values of these sums, where S = {1, 3, 5, 7}?a)1j Sj j    b)2j Sj c)2j S7. What are the values of the following products?a)100ii b) 10011 ii c)40!ii
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Solution

  1. Vamos a resolver las sumas paso a paso:

a) jS(1+j)\sum_{j \in S} (1 + j)

Dado que S={1,3,5,7}S = \{1, 3, 5, 7\}, sumamos 1+j1 + j para cada jj en SS:

(1+1)+(1+3)+(1+5)+(1+7)=2+4+6+8=20 (1 + 1) + (1 + 3) + (1 + 5) + (1 + 7) = 2 + 4 + 6 + 8 = 20

b) jS2j\sum_{j \in S} 2j

Sumamos 2j2j para cada jj en SS:

21+23+25+27=2+6+10+14=32 2 \cdot 1 + 2 \cdot 3 + 2 \cdot 5 + 2 \cdot 7 = 2 + 6 + 10 + 14 = 32

c) jSj2\sum_{j \in S} j^2

Sumamos j2j^2 para cada jj en SS:

12+32+52+72=1+9+25+49=84 1^2 + 3^2 + 5^2 + 7^2 = 1 + 9 + 25 + 49 = 84

  1. Vamos a resolver los productos paso a paso:

a) i=1100i\prod_{i=1}^{100} i

Este producto es el factorial de 100, denotado como 100!100!:

100!=100×99×98××2×1 100! = 100 \times 99 \times 98 \times \cdots \times 2 \times 1

b) i=1100(1i)\prod_{i=1}^{100} (1 - i)

Para cada ii de 1 a 100, calculamos 1i1 - i:

(11)×(12)×(13)××(1100) (1 - 1) \times (1 - 2) \times (1 - 3) \times \cdots \times (1 - 100)

El primer término es 11=01 - 1 = 0, por lo tanto, el producto total es 0.

c) i=140i\prod_{i=1}^{40} i

Este producto es el factorial de 40, denotado como 40!40!:

40!=40×39×38××2×1 40! = 40 \times 39 \times 38 \times \cdots \times 2 \times 1

This problem has been solved

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