In part B of the experiment, using the Michelson Interferometer, the wavelength λ of the laser is determined. The air chamber is first evacuated and then as the air is let back in slowly the change in the number of interference fringes, N, is counted.The interference pattern changes because the path length in one of the arms of the interferometer is altered due to the change in refractive index in the air chamber.There are two possible sources of systematic errors:1. If the air leaks in to the chamber too fast this can make counting the fringe change difficult (it is easy to miss some).2. All the air can't be pumped out of the chamber (a perfect vacuum can't be formed).How will these effect your value of λ found?Select one:a.It will be too large.b.It will be too small.c.It will have no effect as the errors cancel out. Since 1. leads to λ being too large and 2. to λ being too small.d.It will have no effect as the errors cancel out. Since 1. leads to λ being too small and 2. to λ being too large.e.It will have no effect since these are just random errors.

In part A of the experiment a pair of slits are illuminated with a laser and an interference pattern is observed. The slit spacing is d = 0.0001 m and the pattern is projected on to the wall a distance L= 2.35 m from the slits. From one dark spot 7 further dark spots are counted and the distance is measured to be Z = 0.093 m.Calculate the wavelength λ of the laser.

In part A of the experiment a pair of slits are illuminated with a laser and an interference pattern is observed. The slit spacing is d = (0.100 ± 0.003) mm and the pattern is projected on to the wall a distance L= (2.352 ± 0.019) m from the slits. From a dark spot 8 further dark spots are counted and the distance is measured to be Z = (12.2 ± 0.1) cm.The wavelength of the laser is calculated to be λ = 648 nm.Calculate the uncertainty in the wavelength. Express answer in nm (1x10-9m) to the nearest whole number.

If light illuminates a double slit an interference pattern of alternating bright and dark spots is seen. The intensity of the bright spots is brighter at the centre due to the width of the slits. The bright interference fringes will be readily observed inside the broad central diffraction maximum. Outside this they will be much fainter.A laser of wavelength λ = 650 nm is shone on a pair of slits each of width a = 14 µm. The slit spacing is d = 0.3 mm. The resulting interference pattern is projected on to a screen a distance L= 2.6 m from the double slit.Counting out from the (n= 0) central bright interference fringe, how many more bright interference fringes will be seen before the intensity drops to zero at the edge of the central diffraction maximum.Express your answer to the nearest whole number.

Shown below is a diagram of a Michelson Interferometer. In the experiment an air chamber is placed in between the beam splitter and mirror 2. If the chamber is evacuated (the air removed) this has the same effect asSelect one:a.moving mirror 2 towards the beam splitter.b.moving mirror 2 away from the beam splitter.c.you need to move mirror 1 as well as mirror 2.d.moving the mirrors can't reproduce the effect of evacuating the chamber.

In part A of the experiment a hair is illuminated with a laser and a diffraction pattern is observed. The wavelength λ = (648 ± 12) nm and the pattern is projected on to the wall a distance L = (2.226 ± 0.003) m from the hair. The distance across the central maximum is measured to be 2y= (0.048 ± 0.001) m.The width of the hair is calculated to be a= 60.1 µmCalculate the uncertainty in the width of the hair Δa in µm, to one decimal place. You do not need to specify the units.