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In an arithmetic progression the first term is 5 and its common difference is 3. If the general term is an , find a18 - a13.

Question

In an arithmetic progression the first term is 5 and its common difference is 3. If the general term is an , find a18 - a13.

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Solution

In an arithmetic progression, the nth term (an) can be found using the formula:

an = a + (n - 1)d

where: a is the first term, d is the common difference, and n is the term number.

Given that the first term (a) is 5 and the common difference (d) is 3, we can find the 18th term (a18) and the 13th term (a13) as follows:

a18 = a + (18 - 1)d = 5 + (18 - 1)3 = 5 + 51 = 56 a13 = a + (13 - 1)d = 5 + (13 - 1)3 = 5 + 36 = 41

The difference between the 18th term and the 13th term is:

a18 - a13 = 56 - 41 = 15

So, a18 - a13 = 15.

This problem has been solved

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