194400 can be expressed in exponential form as 2^5 * 3^2 * 5^2 * 7^3. Here's how we get that:

1. Prime factorize 194400. The prime factors are 2, 3, 5, and 7.
2. Count the number of times each prime factor appears. The counts are 5, 2, 2, and 3 respectively.
3. Write the prime factorization in exponential form. This gives us 2^5 * 3^2 * 5^2 * 7^3.

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194400 can be expressed in exponential form as 2^5 * 3^2 * 5^2 * 7^3. Here's how we get that:

1. Prime factorize 194400. The prime factors are 2, 3, 5, and 7.
2. Count the number of times each prime factor appears. The counts are 5, 2, 2, and 3 respectively.
3. Write the prime factorization in exponential form. This gives us 2^5 * 3^2 * 5^2 * 7^3.

Knowee AI · Accepted Answer

194400 can be expressed in exponential form as 2^5 * 3^2 * 5^2 * 7^3. Here's how we get that:

1. Prime factorize 194400. The prime factors are 2, 3, 5, and 7.
2. Count the number of times each prime factor appears. The counts are 5, 2, 2, and 3 respectively.
3. Write the prime factorization in exponential form. This gives us 2^5 * 3^2 * 5^2 * 7^3.

express 194400 in exponential form

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