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A baseball leaves the hand of an outfielder at an angle of 35 degrees from the horizontal with a resultant velocity of 30m/s. If air resistance is negligible, what is the horizontal velocity throughout its flightQuestion 18Answera.17.5 m/sb.17.2 m/sc.30.3 m/sd.15 m/se.24.6 m/s

Question

A baseball leaves the hand of an outfielder at an angle of 35 degrees from the horizontal with a resultant velocity of 30m/s. If air resistance is negligible, what is the horizontal velocity throughout its flightQuestion 18Answera.17.5 m/sb.17.2 m/sc.30.3 m/sd.15 m/se.24.6 m/s

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Solution

The horizontal velocity (Vx) of a projectile can be calculated using the formula:

Vx = V * cos(θ)

where: V is the resultant velocity (30 m/s in this case) θ is the angle from the horizontal (35 degrees in this case)

So,

Vx = 30 m/s * cos(35 degrees)

Using a calculator, the cosine of 35 degrees is approximately 0.819.

Therefore,

Vx = 30 m/s * 0.819 = 24.57 m/s

So, the horizontal velocity throughout its flight is approximately 24.57 m/s. The closest answer to this is e. 24.6 m/s.

This problem has been solved

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