What will be the output of the following code snippet?stack = [1, 2, 3]stack.append(4)stack.extend([5, 6]) stack.pop()stack.pop()print(stack)Options[1, 2][1, 2, 3, 4][1, 2, 3][1, 2, 5, 6]
Question
What will be the output of the following code snippet?stack = [1, 2, 3]stack.append(4)stack.extend([5, 6]) stack.pop()stack.pop()print(stack)Options[1, 2][1, 2, 3, 4][1, 2, 3][1, 2, 5, 6]
Solution
The output of the given code snippet will be [1, 2, 3]. Here's the step by step explanation:
- We start with a stack of [1, 2, 3].
- The append(4) function adds the number 4 to the end of the stack, making it [1, 2, 3, 4].
- The extend([5, 6]) function adds the numbers 5 and 6 to the end of the stack, making it [1, 2, 3, 4, 5, 6].
- The pop() function removes the last element from the stack, which is 6, making the stack [1, 2, 3, 4, 5].
- Another pop() function removes the last element from the stack, which is 5, making the stack [1, 2, 3, 4].
- The print(stack) function prints the current state of the stack, which is [1, 2, 3, 4].
So, the correct option is [1, 2, 3, 4]. However, there seems to be a mistake in the options provided as none of them match the correct output.
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