create a AVL tree whose element is 55,25, 65, 9,8,15
Question
create a AVL tree whose element is 55,25, 65, 9,8,15
Solution
Sure, let's create an AVL tree with the elements 55, 25, 65, 9, 8, 15.
Step 1: Start with the first element, 55. This becomes the root of the tree.
Step 2: Insert the second element, 25. Since 25 is less than 55, it becomes the left child of 55.
Step 3: Insert the third element, 65. Since 65 is greater than 55, it becomes the right child of 55.
So far, the tree looks like this:
55
/ \
25 65
Step 4: Insert the fourth element, 9. Since 9 is less than 55 and also less than 25, it becomes the left child of 25.
Step 5: Insert the fifth element, 8. Since 8 is less than all other elements, it becomes the left child of 9.
Step 6: Insert the sixth element, 15. Since 15 is less than 55 but greater than 9, it becomes the right child of 9.
Now, the tree looks like this:
55
/ \
25 65
/
9
/ \
8 15
Step 7: Now, we need to check if the tree is balanced. The balance factor of a node is the height of its left subtree minus the height of its right subtree. An AVL tree is a binary search tree in which the balance factor of every node is either -1, 0, or 1. If the balance factor of any node is not in this range, we need to balance the tree by performing rotations.
In this case, the node with value 25 has a balance factor of 2 (height of left subtree is 3 and height of right subtree is 0), which means the tree is not balanced. We need to perform a right rotation on the node with value 25.
After the right rotation, the tree becomes:
55
/ \
9 65
/ \
8 25
/
15
Step 8: The tree is still not balanced because the node with value 55 has a balance factor of 2. We need to perform a left rotation on the node with value 55.
After the left rotation, the final AVL tree becomes:
9
/ \
8 55
/ \
25 65
/
15
This is the final AVL tree for the given elements.
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