Write the prime factors of 72 in index notation.A23×32B23×33C24×33D21×32E23×3×11

First, we need to find the prime factors of 72.

Step 1: Start by dividing the number by the smallest prime number, which is 2. 72 ÷ 2 = 36.

Step 2: Continue this process. 36 ÷ 2 = 18.

Step 3: Continue dividing by 2. 18 ÷ 2 = 9.

Step 4: Now, 9 cannot be divided evenly by 2, so we move on to the next prime number, which is 3. 9 ÷ 3 = 3.

Step 5: Finally, 3 ÷ 3 = 1.

So, the prime factors of 72 are 2, 2, 2, 3, and 3.

In index notation, this is written as 2^3 × 3^2.

Therefore, the correct answer is A: 2^3 × 3^2.