What will be the output of the following code snippet?#include <stdio.h>int main(){int a = 3, b = 5;int t = a;a = b;b = t;printf("%d %d", a, b);return 0;}a.3 5b.3 3c.5 5d.5 3

The output of the code will be "5 3".

Here's the step by step explanation:

1. The code starts with the declaration of two integer variables 'a' and 'b' with values 3 and 5 respectively.
2. Then, a third integer variable 't' is declared and is assigned the value of 'a', which is 3.
3. The value of 'b' (which is 5) is then assigned to 'a'. So now, 'a' becomes 5.
4. The value of 't' (which is 3) is then assigned to 'b'. So now, 'b' becomes 3.
5. Finally, the printf function prints the values of 'a' and 'b', which are 5 and 3 respectively.

So, the correct answer is d. 5 3.