There are two identical small holes on the opposite sides of a tank containing a liquid. The tank is open at the top. The difference in height of the two holes is h as shown in the figure. As the liquid comes out of the two holes, the tank will experience a net horizontal force proportional to:
Question
There are two identical small holes on the opposite sides of a tank containing a liquid. The tank is open at the top. The difference in height of the two holes is h as shown in the figure. As the liquid comes out of the two holes, the tank will experience a net horizontal force proportional to:
Solution
The tank will experience a net horizontal force proportional to zero. This is because the two holes are identical and on opposite sides of the tank. The liquid coming out of the two holes will exert equal and opposite forces on the tank, resulting in a net horizontal force of zero.
Here are the steps to understand this:
-
When the liquid comes out of the holes, it exerts a force on the tank. This is due to Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
-
The force exerted by the liquid coming out of the hole is proportional to the speed of the liquid. The speed of the liquid, in turn, is determined by the height of the liquid above the hole, according to Torricelli's law.
-
Since the two holes are at different heights, the speeds of the liquid coming out of the two holes are different. However, the difference in speeds does not result in a net horizontal force on the tank.
-
This is because the forces exerted by the liquid coming out of the two holes are in opposite directions. Therefore, they cancel each other out, resulting in a net horizontal force of zero.
-
Therefore, the net horizontal force on the tank is not proportional to the difference in height of the two holes, the speed of the liquid, or any other factor. It is always zero, as long as the two holes are identical and on opposite sides of the tank.
Similar Questions
A jet of water squirts out horizontally from a hole near the bottom of the tank shown in the figure. If the hole has a diameter of 4.95 mm, what is the height h of the water level in the tank?
A large open tank has two holes in the wall. One is a square hole of side L at a depth ‘y’ from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then R = (Assume R and L << y)
Equal mass of three liquids are kept in three identical cylindrical vessel A,B and C. The densities are ρA< ρB< ρC.The force on the base will be
Consider a cylindrical tank of radius 1m is filled with water. The top surface of water is at 15 m from the bottom of the cylinder. There is a hole on the wall of cylinder at a height of 5m from the bottom. A force of 5 × 105 N is applied an the top surface of water using a piston. The speed of efflux from the hole will be: (Assume that there is no atmosphere above the piston)
Explain pressure at the bottom of a liquid
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.