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Denise works in a medical laboratory on different shifts. Any shifts between 7:00 am to 6:00 pm pays $29.50/h. Any other times from 6:00 pm to 7:00 am pays a shift premium of $1.55/h. One week Denise worked the first 4 days from 7:00 am to 3:00 pm and then 3 days from 3:00 pm to 1:00 am.Enter the numbers only with no dollar signs in the answer boxes:1) How many hours in total did Denise work?2) What were her earnings for the week at her regular wage?

Question

Denise works in a medical laboratory on different shifts. Any shifts between 7:00 am to 6:00 pm pays 29.50/h.Anyothertimesfrom6:00pmto7:00ampaysashiftpremiumof29.50/h. Any other times from 6:00 pm to 7:00 am pays a shift premium of 1.55/h. One week Denise worked the first 4 days from 7:00 am to 3:00 pm and then 3 days from 3:00 pm to 1:00 am.Enter the numbers only with no dollar signs in the answer boxes:1) How many hours in total did Denise work?2) What were her earnings for the week at her regular wage?

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Solution

  1. Denise worked 4 days from 7:00 am to 3:00 pm, which is 8 hours per day. So for the first 4 days, she worked 4*8 = 32 hours.

Then she worked 3 days from 3:00 pm to 1:00 am, which is 10 hours per day. So for the next 3 days, she worked 3*10 = 30 hours.

So in total, Denise worked 32 + 30 = 62 hours.

  1. For the first 4 days, she worked 8 hours per day at a rate of 29.50/h.Soherearningsforthesedayswere4∗8∗29.50/h. So her earnings for these days were 4*8*29.50 = $948.

For the next 3 days, she worked 8 hours per day (from 3:00 pm to 11:00 pm) at the same rate, and 2 hours per day (from 11:00 pm to 1:00 am) at a rate of 29.50/h+29.50/h + 1.55/h = 31.05/h.Soherearningsforthesedayswere3∗(8∗31.05/h. So her earnings for these days were 3*(8*29.50 + 2*31.05)=31.05) = 897.9.

So her total earnings for the week at her regular wage were 948+948 + 897.9 = $1845.9.

This problem has been solved

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