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Select the code snippet which performs unordered linear search iteratively?Select one:None of these optionspublic int UnorderedLinearSearch(int[] arr, int size, int data){    int index=0;    for(int i = 0; i <= size; i++)    {        if(arr[i] == data)        {            index = i;            break;        }    }    return index;}public int UnorderedLinearSearch(int[] arr, int size, int data){    int index;    for(int i = 0; i < size; i++)    {        if(arr[i] == data)        {            break;        }    }    return index;}public int UnorderedLinearSearch(int[] arr, int size, int data){    int index=0;    for(int i = 0; i < size; i++)    {        if(arr[i] == data)        {            index = i;            break;        }    }    return index;}

Question

Select the code snippet which performs unordered linear search iteratively?Select one:None of these optionspublic int UnorderedLinearSearch(int[] arr, int size, int data){    int index=0;    for(int i = 0; i <= size; i++)    {        if(arr[i] == data)        {            index = i;            break;        }    }    return index;}public int UnorderedLinearSearch(int[] arr, int size, int data){    int index;    for(int i = 0; i < size; i++)    {        if(arr[i] == data)        {            break;        }    }    return index;}public int UnorderedLinearSearch(int[] arr, int size, int data){    int index=0;    for(int i = 0; i < size; i++)    {        if(arr[i] == data)        {            index = i;            break;        }    }    return index;}

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Solution

The correct code snippet which performs unordered linear search iteratively is:

public int UnorderedLinearSearch(int[] arr, int size, int data){
    int index=0;
    for(int i = 0; i < size; i++)
    {
        if(arr[i] == data)
        {
            index = i;
            break;
        }
    }
    return index;
}

This code snippet correctly initializes the index variable to 0 and then iterates over the array until it finds the desired data. When it finds the data, it updates the index variable to the current index and breaks the loop. Finally, it returns the index of the found data. If the data is not found, it will return 0.

This problem has been solved

Similar Questions

Which of the following code snippet performs linear search recursively? for(i=0;i<n;i++) { if(a[i]==key) printf("element found"); } LinearSearch(int[] a, n,key) { if(n<1) return False if(a[n]==key) return True else LinearSearch(a,n-1,key) } LinearSearch(int[] a, n,key) { if(n<1) return True if(a[n]==key) return False else LinearSearch(a,n-1,key) } LinearSearch(int[] a, n,key) { if(n<1) return False if(a[n]==key) return True else LinearSearch(a,n+1,key) }

Choose the code snippet which uses recursion for linear search.public void linSearch(int[] arr, int first, int last, int key){ if(first == last) { System.out.print("-1"); } else { if(arr[first] == key) { System.out.print(first); } else { linSearch(arr, first+1, last, key); } }} public void linSearch(int[] arr, int first, int last, int key) { if(first == last) { System.out.print("-1"); } else { if(arr[first] == key) { System.out.print(first); } else { linSearch(arr, first+1, last-1, key); } } }public void linSearch(int[] arr, int first, int last, int key){ if(first == last) { System.out.print("-1"); } else { if(arr[first] == key) { System.out.print(last); } else { linSearch(arr, first+1, last, key); } }}public void linSearch(int[] arr, int first, int last, int key){ if(first == last) { System.out.print("-1"); } else { if(arr[first] == key) { System.out.print(first); } else { linSearch(arr, first+1, last+1, key); } }}

Choose the scenario(s) when we need to use Linear search?Select one or more:None of these optionsCan use all the timeWhen performing a single search in an un-ordered listWhen the list has only a few elements

In which of the following cases is a linear search particularly inefficient?Searching in a small arraySearching in a sorted arraySearching in a large, unsorted arraySearching for the first elemen

Linear search(recursive) algorithm used in _____________

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