The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is
Question
The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is
Solution
The nature of the roots of a quadratic equation is determined by the discriminant, which is given by the formula D = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
In this case, the quadratic equation is 9x² - 6x - 2 = 0, so a = 9, b = -6, and c = -2.
Substituting these values into the formula for the discriminant gives:
D = (-6)² - 49(-2) = 36 + 72 = 108
Since the discriminant is positive, the quadratic equation has two distinct real roots.
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