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The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is

Question

The nature of roots of the quadratic equation 9x2 – 6x – 2 = 0 is

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Solution

The nature of the roots of a quadratic equation is determined by the discriminant, which is given by the formula D = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.

In this case, the quadratic equation is 9x² - 6x - 2 = 0, so a = 9, b = -6, and c = -2.

Substituting these values into the formula for the discriminant gives:

D = (-6)² - 49(-2) = 36 + 72 = 108

Since the discriminant is positive, the quadratic equation has two distinct real roots.

This problem has been solved

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