The value of log (9/8) - log (27/32) + log (3/4) is_____?

To solve this problem, we need to use the properties of logarithms.

Step 1: Use the property of logarithms log(a/b) = log(a) - log(b)

log (9/8) - log (27/32) + log (3/4) = log(9) - log(8) - log(27) + log(32) + log(3) - log(4)

Step 2: Simplify the equation

= log(9) - log(2^3) - log(3^3) + log(2^5) + log(3) - log(2^2)

Step 3: Use the property of logarithms log(a^n) = n*log(a)

= log(9) - 3log(2) - 3log(3) + 5log(2) + log(3) - 2log(2)

Step 4: Simplify the equation

= 2log(3) - 3log(2) - 3log(3) + 5log(2) + log(3) - 2*log(2)

Step 5: Combine like terms

= 2log(3) - 3log(3) + log(3) + 5log(2) - 3log(2) - 2*log(2)

Step 6: Simplify the equation

= 0

So, the value of log (9/8) - log (27/32) + log (3/4) is 0.