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A paper ball is released from rest, and goes on to fall through a large vertical distance. As it falls through the air, it is acted upon by two forces – air resistance and its weight. Which of the following correctly describes its motion after it is dropped?It will accelerate at an increasing rate and then reach its terminal velocityIt will accelerate uniformly before reaching its terminal velocityIt will accelerate uniformlyIt will accelerate at a decreasing rate and then reach its terminal velocity

Question

A paper ball is released from rest, and goes on to fall through a large vertical distance. As it falls through the air, it is acted upon by two forces – air resistance and its weight. Which of the following correctly describes its motion after it is dropped?It will accelerate at an increasing rate and then reach its terminal velocityIt will accelerate uniformly before reaching its terminal velocityIt will accelerate uniformlyIt will accelerate at a decreasing rate and then reach its terminal velocity

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Solution

The correct description of the motion of the paper ball after it is dropped is: "It will accelerate at an increasing rate and then reach its terminal velocity."

Here's the step-by-step explanation:

  1. When the paper ball is first dropped, it starts to accelerate due to the force of gravity. This is the only force acting on it at this point, so it accelerates at a constant rate (approximately 9.8 m/s², the acceleration due to gravity).

  2. As the paper ball speeds up, the air resistance acting on it also increases. This force opposes the motion of the ball, so it starts to reduce the acceleration.

  3. Eventually, the paper ball reaches a speed where the force of air resistance equals the force of gravity. At this point, the forces balance out and the ball stops accelerating. This speed is known as the terminal velocity.

  4. After reaching its terminal velocity, the paper ball continues to fall at a constant speed. It doesn't accelerate anymore because the forces acting on it are balanced.

This problem has been solved

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