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Given a table bugs(id, token, title, category, device, reported_at, created_at, updated_at). Select all distinct bug categories. Your query should output a table with the following columns (category)

Question

Given a table bugs(id, token, title, category, device, reported_at, created_at, updated_at). Select all distinct bug categories. Your query should output a table with the following columns (category)

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Solution

Sure, here is the SQL query to select all distinct bug categories from the given table:

SELECT DISTINCT category
FROM bugs;

This query will return a table with a single column "category" containing all unique bug categories present in the "bugs" table.

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Given a table bugs(id, token, title, category, device, reported_at, created_at, updated_at), find the title of the bug with token = token660 and reported_at on 2020-08-30. Your query should output a table with the following columns (title).

Given a table bugs(id, token, title, category, device, reported_at, created_at, updated_at), find how many bugs were created on 2019-03-01 or later. Your query should output a table with the following columns (count).

how to get every thing from table in sql

SELECT DISTINCT el.device_id, DATE(el.create_time) date, CASE WHEN el.platform IN ('') THEN 'null' ELSE 'unknown' END AS platform_div, CASE WHEN el.event_id='home_page_view' THEN 1 ELSE 0,caseWHEN ud.country ='' THEN 'unknown' ELSE 'developing_country' END AS country_div FROM event_logs el JOIN user_devices ud ON el.device_id = ud.device_id我要如何在查询结果中加入每个device_id使用过的次数

4. What is the SQL to do this result?

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