The reaction between copper and sulfuric acid can be represented by the following chemical equation:

Cu + H2SO4 - CuSO4 + H2O + SO2

Here's the step-by-step process:

1. Copper (Cu) reacts with sulfuric acid (H2SO4). This is a redox reaction, where copper is oxidized and the hydrogen in the sulfuric acid is reduced.

2. The copper replaces the hydrogen in the sulfuric acid, forming copper (II) sulfate (CuSO4).

3. Water (H2O) is also formed in the process, as the hydrogen from the sulfuric acid combines with oxygen.

4. Sulfur dioxide (SO2) is the other product of this reaction. It is formed when the sulfur in the sulfuric acid is reduced.

Please note that this reaction is not typically observed in a high school laboratory setting, as it requires a high temperature to proceed and produces sulfur dioxide, a toxic gas.

Question

The reaction between copper and sulfuric acid can be represented by the following chemical equation:

Cu + H2SO4 -> CuSO4 + H2O + SO2

Here's the step-by-step process:

1. Copper (Cu) reacts with sulfuric acid (H2SO4). This is a redox reaction, where copper is oxidized and the hydrogen in the sulfuric acid is reduced.

2. The copper replaces the hydrogen in the sulfuric acid, forming copper (II) sulfate (CuSO4).

3. Water (H2O) is also formed in the process, as the hydrogen from the sulfuric acid combines with oxygen.

4. Sulfur dioxide (SO2) is the other product of this reaction. It is formed when the sulfur in the sulfuric acid is reduced.

Please note that this reaction is not typically observed in a high school laboratory setting, as it requires a high temperature to proceed and produces sulfur dioxide, a toxic gas.

Knowee AI · Accepted Answer

The reaction between copper and sulfuric acid can be represented by the following chemical equation:

Cu + H2SO4 -> CuSO4 + H2O + SO2

Here's the step-by-step process:

1. Copper (Cu) reacts with sulfuric acid (H2SO4). This is a redox reaction, where copper is oxidized and the hydrogen in the sulfuric acid is reduced.

2. The copper replaces the hydrogen in the sulfuric acid, forming copper (II) sulfate (CuSO4).

3. Water (H2O) is also formed in the process, as the hydrogen from the sulfuric acid combines with oxygen.

4. Sulfur dioxide (SO2) is the other product of this reaction. It is formed when the sulfur in the sulfuric acid is reduced.

Please note that this reaction is not typically observed in a high school laboratory setting, as it requires a high temperature to proceed and produces sulfur dioxide, a toxic gas.

7) Copper and sulfuric acid react to form copper (II) sulfate and water and sulfur dioxide.

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