Which of the following options remain true for case constants in a switch construct?Select one:a.If no case matches and there is no default label, then no further action is taken and the switch statement completes abnormallyb.If no case matches and there is no default label, then it will result in a compilation errorc.If any one of the case constants has a match with the expression, then all statements after the matching case label in the switch block are executed in sequenced.The code with the switch construct gives a compilation error when there is a duplicate case label e.If no case matches but there is a default label, then all statements after the matching default label in the switch block are executed in sequence.
Question
Which of the following options remain true for case constants in a switch construct?Select one:a.If no case matches and there is no default label, then no further action is taken and the switch statement completes abnormallyb.If no case matches and there is no default label, then it will result in a compilation errorc.If any one of the case constants has a match with the expression, then all statements after the matching case label in the switch block are executed in sequenced.The code with the switch construct gives a compilation error when there is a duplicate case label e.If no case matches but there is a default label, then all statements after the matching default label in the switch block are executed in sequence.
Solution
The correct options are:
c. If any one of the case constants has a match with the expression, then all statements after the matching case label in the switch block are executed in sequence.
d. The code with the switch construct gives a compilation error when there is a duplicate case label.
e. If no case matches but there is a default label, then all statements after the matching default label in the switch block are executed in sequence.
Option a is incorrect because if no case matches and there is no default label, the switch statement simply ends normally, not abnormally.
Option b is also incorrect because it will not result in a compilation error if no case matches and there is no default label. The switch statement will just not execute any block of code.
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