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Mrs. Molina bought ice cream treats for 18 children. Each child picked either a sundae or a milkshake. The sundaes cost $1 each and the milkshakes cost $4 each. If Mrs. Molina spent a total of $57, how many of each type of treat did she buy?

Question

Mrs. Molina bought ice cream treats for 18 children. Each child picked either a sundae or a milkshake. The sundaes cost 1eachandthemilkshakescost1 each and the milkshakes cost 4 each. If Mrs. Molina spent a total of $57, how many of each type of treat did she buy?

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Solution

Let's denote the number of sundaes as S and the number of milkshakes as M.

From the problem, we know two things:

  1. S + M = 18 (because there are 18 children and each child picked either a sundae or a milkshake)
  2. 1∗S+1*S + 4*M = 57(becausethesundaescost57 (because the sundaes cost 1 each and the milkshakes cost 4each,andMrs.Molinaspentatotalof4 each, and Mrs. Molina spent a total of 57)

We can solve these equations step by step:

Step 1: From equation 1, we can express S in terms of M: S = 18 - M

Step 2: Substitute S in equation 2: 1∗(18−M)+1*(18 - M) + 4*M = $57

Step 3: Simplify the equation: 18 - M + 4M = 57

Step 4: Combine like terms: 3M + 18 = 57

Step 5: Subtract 18 from both sides: 3M = 39

Step 6: Divide both sides by 3: M = 13

Step 7: Substitute M = 13 in equation 1: S + 13 = 18

Step 8: Subtract 13 from both sides: S = 5

So, Mrs. Molina bought 5 sundaes and 13 milkshakes.

This problem has been solved

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