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A is thrice as good as B and he is able to finish the work 60 days less than B. In how many days they will finish the same work together

Question

A is thrice as good as B and he is able to finish the work 60 days less than B. In how many days they will finish the same work together

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Solution

Sure, let's solve this step by step:

Step 1: Let's assume the time taken by B alone to finish the work is x days.

Step 2: Since A is thrice as good as B, A will take x/3 days to finish the same work.

Step 3: According to the problem, A takes 60 days less than B to finish the work. So, x/3 = x - 60.

Step 4: Solving this equation, we get x = 90 days. So, B alone can finish the work in 90 days and A alone can finish the work in 90/3 = 30 days.

Step 5: If A and B work together, they can finish 1/30 + 1/90 = 4/90 of the work in a day.

Step 6: Therefore, A and B together can finish the work in 90/4 = 22.5 days.

This problem has been solved

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