Here is a step-by-step solution in Python:

1. Define a function `isSpecial` that takes an array `nums` as input.
2. Iterate over the array from the first element to the second last element. For each element, check if it and the next element have different parity. You can do this by checking if the remainder when the current element and the next element are divided by 2 are different. If they are the same, return `False`.
3. If you have checked all pairs and none of them have the same parity, return `True`.

Here is the Python code:

```python
def isSpecial(nums):
for i in range(len(nums) - 1):
if nums[i] % 2 == nums[i + 1] % 2:
return False
return True
```

You can test this function with the provided examples:

```python
print(isSpecial([1])) # Output: True
print(isSpecial([2, 1, 4])) # Output: True
print(isSpecial([4, 3, 1, 6])) # Output: False
```

This function works by checking each pair of adjacent elements in the array. If any pair has the same parity (both even or both odd), the function immediately returns `False`. If it checks all pairs and none of them have the same parity, it returns `True`.

Question

Here is a step-by-step solution in Python:

1. Define a function `isSpecial` that takes an array `nums` as input.
2. Iterate over the array from the first element to the second last element. For each element, check if it and the next element have different parity. You can do this by checking if the remainder when the current element and the next element are divided by 2 are different. If they are the same, return `False`.
3. If you have checked all pairs and none of them have the same parity, return `True`.

Here is the Python code:

```python
def isSpecial(nums):
    for i in range(len(nums) - 1):
        if nums[i] % 2 == nums[i + 1] % 2:
            return False
    return True
```

You can test this function with the provided examples:

```python
print(isSpecial([1]))  # Output: True
print(isSpecial([2, 1, 4]))  # Output: True
print(isSpecial([4, 3, 1, 6]))  # Output: False
```

This function works by checking each pair of adjacent elements in the array. If any pair has the same parity (both even or both odd), the function immediately returns `False`. If it checks all pairs and none of them have the same parity, it returns `True`.

Knowee AI · Accepted Answer

Here is a step-by-step solution in Python:

1. Define a function `isSpecial` that takes an array `nums` as input.
2. Iterate over the array from the first element to the second last element. For each element, check if it and the next element have different parity. You can do this by checking if the remainder when the current element and the next element are divided by 2 are different. If they are the same, return `False`.
3. If you have checked all pairs and none of them have the same parity, return `True`.

Here is the Python code:

```python
def isSpecial(nums):
    for i in range(len(nums) - 1):
        if nums[i] % 2 == nums[i + 1] % 2:
            return False
    return True
```

You can test this function with the provided examples:

```python
print(isSpecial([1]))  # Output: True
print(isSpecial([2, 1, 4]))  # Output: True
print(isSpecial([4, 3, 1, 6]))  # Output: False
```

This function works by checking each pair of adjacent elements in the array. If any pair has the same parity (both even or both odd), the function immediately returns `False`. If it checks all pairs and none of them have the same parity, it returns `True`.

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