What is the expected mass percent result, determined by elemental analysis, for carbon in a molecule with a molecular formula C2H3O2? Provide your answer as a percentage (out of 100) to 2 decimal place but DO NOT include the percentage sign in your answer.Use the following mass units in your calculation:Carbon: 12.01 g/molHydrogen: 1.01 g/molOxygen: 16.00 g/mol
Question
What is the expected mass percent result, determined by elemental analysis, for carbon in a molecule with a molecular formula C2H3O2? Provide your answer as a percentage (out of 100) to 2 decimal place but DO NOT include the percentage sign in your answer.Use the following mass units in your calculation:Carbon: 12.01 g/molHydrogen: 1.01 g/molOxygen: 16.00 g/mol
Solution
First, we need to calculate the molar mass of the molecule C2H3O2.
The molar mass of the molecule is the sum of the molar masses of all the atoms in the molecule.
For C2H3O2, the molar mass is:
(2 * 12.01 g/mol for Carbon) + (3 * 1.01 g/mol for Hydrogen) + (2 * 16.00 g/mol for Oxygen)
= 24.02 g/mol + 3.03 g/mol + 32.00 g/mol
= 59.05 g/mol
Next, we need to calculate the mass percent of carbon in the molecule.
The mass percent of an element in a compound is the mass of the element divided by the total mass of the compound, multiplied by 100.
For carbon in C2H3O2, the mass percent is:
(24.02 g/mol / 59.05 g/mol) * 100
= 40.67
So, the expected mass percent result for carbon in a molecule with a molecular formula C2H3O2 is 40.67.
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