John pulls a 50 kg crate with a force of 215 N to the right. There is a frictional force of 200 N acting to the left, between the crate and the ground. Alan assists John by pushing the crate with a force of 300 N also to the right.What is the acceleration of the trolley in m/s2?
Question
John pulls a 50 kg crate with a force of 215 N to the right. There is a frictional force of 200 N acting to the left, between the crate and the ground. Alan assists John by pushing the crate with a force of 300 N also to the right.What is the acceleration of the trolley in m/s2?
Solution
To find the acceleration of the crate, we first need to find the net force acting on it.
Step 1: Calculate the total force acting to the right. This is the sum of the forces applied by John and Alan, which is 215 N + 300 N = 515 N.
Step 2: Subtract the force of friction, which is acting to the left. The net force is therefore 515 N - 200 N = 315 N.
Step 3: Use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). We can rearrange this formula to solve for acceleration (a = F/m).
Step 4: Substitute the values into the formula: a = 315 N / 50 kg = 6.3 m/s².
So, the acceleration of the crate is 6.3 m/s².
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