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If a = 4.36, b = 2.39, c = 1.97, then the value of a3-b3-c3-3abc is

Question

If a = 4.36, b = 2.39, c = 1.97, then the value of a3-b3-c3-3abc is

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Solution

The given expression is a^3 - b^3 - c^3 - 3abc.

Step 1: Substitute the given values into the expression.

= (4.36)^3 - (2.39)^3 - (1.97)^3 - 3*(4.36)(2.39)(1.97)

Step 2: Calculate the cube of each number.

= 83.14496 - 13.654619 - 7.661933 - 3*(4.36)(2.39)(1.97)

Step 3: Multiply the numbers in the last term.

= 83.14496 - 13.654619 - 7.661933 - 3*20.54268

Step 4: Multiply the last term.

= 83.14496 - 13.654619 - 7.661933 - 61.62804

Step 5: Subtract the numbers.

= -0.799632

So, the value of a^3 - b^3 - c^3 - 3abc when a = 4.36, b = 2.39, c = 1.97 is approximately -0.80.

This problem has been solved

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