Select the correct answerWhat will be the output of the following Java program? class CT { public static void main(String args[]) { try { int x, y; y = 0; x = 5 / y; System.out.print("A"); } catch(ArithmeticException e) { System.out.print("B"); } } }OptionsACompilation ErrorRuntime ErrorB
Question
Select the correct answerWhat will be the output of the following Java program? class CT { public static void main(String args[]) { try { int x, y; y = 0; x = 5 / y; System.out.print("A"); } catch(ArithmeticException e) { System.out.print("B"); } } }OptionsACompilation ErrorRuntime ErrorB
Solution
The correct answer is "B".
Here's the step by step explanation:
- The program starts with the main method.
- It declares two integer variables x and y.
- It assigns 0 to y.
- It tries to divide 5 by y (which is 0). In Java, division by zero is not allowed and will throw an ArithmeticException.
- The catch block catches this exception and prints "B".
- Therefore, the output of the program is "B".
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