Knowee
Questions
Features
Study Tools

A card is selected from the set without looking. What is the probability of selecting a heart?

Question

A card is selected from the set without looking. What is the probability of selecting a heart?

🧐 Not the exact question you are looking for?Go ask a question

Solution

To determine the probability of selecting a heart from a standard deck of cards, follow these steps:

  1. Identify the total number of cards in the deck: A standard deck has 52 cards.
  2. Identify the number of hearts in the deck: There are 13 hearts in a standard deck (one for each rank: Ace through King).
  3. Calculate the probability: The probability P P of selecting a heart is given by the ratio of the number of hearts to the total number of cards.

P(heart)=Number of heartsTotal number of cards=1352 P(\text{heart}) = \frac{\text{Number of hearts}}{\text{Total number of cards}} = \frac{13}{52}

  1. Simplify the fraction:

1352=14 \frac{13}{52} = \frac{1}{4}

So, the probability of selecting a heart is 14 \frac{1}{4} or 0.25.

This problem has been solved

Similar Questions

What is the probability of selecting a heart from a deck of cards?

If one card is randomly selected from a well-shuffled standard deck of 52 cards, what is the probability that the card selected is not a heart?

A card is drawn from a well shuffled pack of 52 cards, what is the probability of not getting a heart card?

B) What is the probability that a randomly selected card is diamond or heart from a standard deck of 52 cards?

Two cards are drawn in order without replacement from a regular deck of 52 cards.Write all answers as simplified fractions.What is the probability the first card is a heart?  What is the probability the second card is a red card given the first card was a heart?  What is the probability the first card is a heart and the second card is a red?

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.