A ball is subjected to a pressure of 2.0 atmospheres. The original diameter of the ball is 10.0 cm. The squeezed diameter of the ball is 9.999 cm. The volume strain of the ball is

The volume strain of a material is defined as the ratio of the change in volume to the original volume.

In this case, we first need to calculate the original volume and the squeezed volume of the ball using the formula for the volume of a sphere, which is V = 4/3 * π * (d/2)³.

1. Calculate the original volume: The original diameter of the ball is 10.0 cm, so the radius is 10.0 cm / 2 = 5.0 cm. The original volume is V = 4/3 * π * (5.0 cm)³ = 523.6 cm³.

2. Calculate the squeezed volume: The squeezed diameter of the ball is 9.999 cm, so the radius is 9.999 cm / 2 = 4.9995 cm. The squeezed volume is V = 4/3 * π * (4.9995 cm)³ = 523.583 cm³.

3. Calculate the change in volume: The change in volume is the original volume minus the squeezed volume, which is 523.6 cm³ - 523.583 cm³ = 0.017 cm³.

4. Calculate the volume strain: The volume strain is the change in volume divided by the original volume, which is 0.017 cm³ / 523.6 cm³ = 3.25 x 10^-5.

So, the volume strain of the ball is 3.25 x 10^-5.