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Two cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options240300330270

Question

Two cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options240300330270

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Solution

To solve this problem, we can use the formula for time, which is distance divided by speed.

Let's denote the distance between the two cities as D (in km), the speed of car A as Sa (in km/hr), the speed of car B as Sb (in km/hr), and the time difference as Δt (in hours).

From the problem, we know that Sa = 60 km/hr, Sb = 108 km/hr, and Δt = 2 hours.

The time it takes for car A to travel from one city to another is D/Sa, and for car B it is D/Sb. According to the problem, the time for car A is 2 hours more than the time for car B, so we can write the equation as follows:

D/Sa = D/Sb + Δt

Substituting the known values into the equation, we get:

D/60 = D/108 + 2

To solve for D, we first need to get rid of the denominators by multiplying the whole equation by 60*108, which gives:

108D = 60D + 260108

Solving this equation for D, we get:

48D = 260108

D = (260108) / 48

D = 270 km

So, the distance between the two cities is 270 km.

This problem has been solved

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