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If $2000 is invested at an interest rate of 9% per annum, compounded annually, what will the value of the investment be after 6 years?

Question

If $2000 is invested at an interest rate of 9% per annum, compounded annually, what will the value of the investment be after 6 years?

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Solution

To calculate the value of the investment after 6 years, we can use the formula for compound interest, which is:

A = P (1 + r/n)^(nt)

Where: A = the amount of money accumulated after n years, including interest. P = the principal amount (the initial amount of money) r = annual interest rate (in decimal) n = number of times that interest is compounded per year t = the time the money is invested for in years

In this case: P = $2000 r = 9% per annum = 0.09 (in decimal) n = 1 (since the interest is compounded annually) t = 6 years

Substituting these values into the formula, we get:

A = 2000 (1 + 0.09/1)^(1*6) A = 2000 (1 + 0.09)^6 A = 2000 * 1.09^6

Now, calculate the value of 1.09^6, then multiply the result by 2000 to get the final amount.

This problem has been solved

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