TaskGiven a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9
Question
TaskGiven a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9
Solution
This task is a simple programming problem. Here is a step-by-step solution in Python:
- First, we need to take an input from the user. In Python, we use the
input()function for this. Since the input is an integer, we also need to convert it to an integer using theint()function.
n = int(input())
- Next, we need to check if the number is less than or equal to 9. If it is, we print the corresponding English word. If it's not, we print "Greater than 9". We can use an
if-elsestatement for this.
if n <= 9:
# print the corresponding English word
else:
print("Greater than 9")
- To print the corresponding English word, we can use a list of words and use the number as an index to get the correct word. Note that we need to subtract 1 from the number because list indices in Python start at 0.
words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
print(words[n-1])
Here is the complete code:
n = int(input())
if n <= 9:
words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
print(words[n-1])
else:
print("Greater than 9")
This code will solve the problem as described.
Similar Questions
Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9
Given a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input
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Given an integer input , whether the given input is "Positive" or "Negative" or "Zero" and print the corresponding messageInput Format:Enter an integer as a input Output Format: Print the output as "Negative" or "Positive" or "Zero"Constraints:1 <= INPUT <= 10^15Sample Input 1:-98Sample Output 1:NEGATIVESample Input 2:0Sample Output 2:ZERO
Write a program to check the given number is perfect or not ?Constraints:1<n<1000Input FormatAn integer nOutput FormatA corresponding stringExample:Input 1:6Output 1:YesInput 2:3Output 2:No
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