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TaskGiven a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9

Question

TaskGiven a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9

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Solution

This task is a simple programming problem. Here is a step-by-step solution in Python:

  1. First, we need to take an input from the user. In Python, we use the input() function for this. Since the input is an integer, we also need to convert it to an integer using the int() function.
n = int(input())
  1. Next, we need to check if the number is less than or equal to 9. If it is, we print the corresponding English word. If it's not, we print "Greater than 9". We can use an if-else statement for this.
if n <= 9:
    # print the corresponding English word
else:
    print("Greater than 9")
  1. To print the corresponding English word, we can use a list of words and use the number as an index to get the correct word. Note that we need to subtract 1 from the number because list indices in Python start at 0.
words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
print(words[n-1])

Here is the complete code:

n = int(input())
if n <= 9:
    words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    print(words[n-1])
else:
    print("Greater than 9")

This code will solve the problem as described.

This problem has been solved

Similar Questions

Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9

Given a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input

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