Frank recently came to Canberra to study at ANU on a two-year program. He rents an apartment inGreenway and decides to buy a used car. The car costs $15000 and the seller offers an optional warranty for twoyears. With the warranty, the seller will repair (or replace) the car for free if the car fails within two years. Thewarranty costs $1800. We will try to decide if Frank should buy the extended warranty.Frank’s utility index is 𝑢(𝑥0) + 11+𝑟 𝑢(𝑥1) + 1(1+𝑟)2 𝑢(𝑥2), where 𝑥0 is his cash flow right now (either -$15000 or-$16000), 𝑥1 is his cash flow during the first year and 𝑥2 is his cash flow during the second year. Here 𝑟 = 5%. Inall cash flows, we only count the cash flows related to the possible failure of the car. Tuition, wage from part-timejobs, fuel and maintenance of the car are all ignored. The function 𝑢 has the following form:𝑢(𝑥) = 40000 ∗(1 + 𝑥20000)1∕2− 40000.To Frank’s best estimation, the car fails within one year with probability .05 and it survives the first year but failsin the second year with probability .07. If the car survives after 𝑡 years, his cash flow in year 𝑡 is zero; if the carfails in year 𝑡 with no warranty, his cash flow in year 𝑡 is -$15000, the cost of buying a replacement. For simplicity,we ignore the possibility that his replacement car, purchased in Year 1, fails in Year 2.(a) [15 marks] Determine if Frank should buy the warranty; for this part, take all the assumptions as given.(b) [5 marks] Discuss whether it is reasonable to assume that the replacement car does not fail. (Limited to 50words.)(c) [10 marks] Discuss why other cash flows such as tuition and fuel may be ignored in the analysis. (Limited to200 words.)(d) [10 marks] Consultant Bob totally disagrees with our analysis in Part (a). He argues that Frank should switchto public transportation if the car fails before he graduates. Fare is $3.2 everyday and thus about $830 ayear. Therefore, Frank’s cash flow after the failure of the car is -$830 a year without the extended warranty.Therefore, the extended warranty is a joke. Evaluate Bob’s method. (Limited to 200 words.
Question
Frank recently came to Canberra to study at ANU on a two-year program. He rents an apartment inGreenway and decides to buy a used car. The car costs 1800. We will try to decide if Frank should buy the extended warranty.Frank’s utility index is 𝑢(𝑥0) + 11+𝑟 𝑢(𝑥1) + 1(1+𝑟)2 𝑢(𝑥2), where 𝑥0 is his cash flow right now (either -16000), 𝑥1 is his cash flow during the first year and 𝑥2 is his cash flow during the second year. Here 𝑟 = 5%. Inall cash flows, we only count the cash flows related to the possible failure of the car. Tuition, wage from part-timejobs, fuel and maintenance of the car are all ignored. The function 𝑢 has the following form:𝑢(𝑥) = 40000 ∗(1 + 𝑥20000)1∕2− 40000.To Frank’s best estimation, the car fails within one year with probability .05 and it survives the first year but failsin the second year with probability .07. If the car survives after 𝑡 years, his cash flow in year 𝑡 is zero; if the carfails in year 𝑡 with no warranty, his cash flow in year 𝑡 is -3.2 everyday and thus about 830 a year without the extended warranty.Therefore, the extended warranty is a joke. Evaluate Bob’s method. (Limited to 200 words.
Solution
(a) To determine if Frank should buy the warranty, we need to calculate his expected utility with and without the warranty.
Without the warranty, his utility is:
u(x0) + 1/(1+r) * [0.05u(-15000) + 0.95u(0)] + 1/(1+r)^2 * [0.07u(-15000) + 0.93u(0)]
Substituting the given values, we get:
40000*(1 - 15000/20000)^(1/2) - 40000 + 1/1.05 * [0.05*(40000*(1 - 15000/20000)^(1/2) - 40000) + 0.95*(40000*(1 - 0/20000)^(1/2) - 40000)] + 1/1.05^2 * [0.07*(40000*(1 - 15000/20000)^(1/2) - 40000) + 0.93*(40000*(1 - 0/20000)^(1/2) - 40000)]
With the warranty, his utility is:
u(x0) + 1/(1+r) * u(0) + 1/(1+r)^2 * u(0)
Substituting the given values, we get:
40000*(1 - 16000/20000)^(1/2) - 40000 + 1/1.05 * (40000*(1 - 0/20000)^(1/2) - 40000) + 1/1.05^2 * (40000*(1 - 0/20000)^(1/2) - 40000)
If the utility with the warranty is higher than the utility without the warranty, Frank should buy the warranty.
(b) It may not be reasonable to assume that the replacement car does not fail. This assumption ignores the risk associated with used cars, which can fail unexpectedly.
(c) Other cash flows such as tuition and fuel may be ignored in the analysis because they are not directly related to the decision of buying the warranty. The decision to buy the warranty only affects the cash flows related to the possible failure of the car.
(d) Bob's method of switching to public transportation if the car fails may not be the best solution for Frank. While the cost of public transportation is lower than the cost of the warranty, it may not provide the same convenience and flexibility as owning a car. Furthermore, the cost of public transportation may increase over time, which is not considered in Bob's analysis. Therefore, the extended warranty may not be a joke as Bob suggests.
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