The integral value of a for which ax2 + ax + a = 2x2 - 3x - 6 has equal roots is 3 2 – 3 – 2
Question
The integral value of a for which ax2 + ax + a = 2x2 - 3x - 6 has equal roots is 3 2 – 3 – 2
Solution
The given equation is ax² + ax + a = 2x² - 3x - 6.
To find the value of 'a' for which the equation has equal roots, we need to equate the coefficients of the corresponding terms on both sides of the equation.
So, we have:
a = 2 (coefficient of x²)
a = -3 (coefficient of x)
a = -6 (constant term)
From the first two equations, we get a = 2 = -3, which is not possible. Hence, there is no real value of 'a' for which the given equation has equal roots.
The statement in the question seems to be incorrect or incomplete.
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