In simple harmonic motion (SHM), the kinetic energy (KE) and potential energy (PE) of the particle are constantly interchanging. At the mean position, the particle has maximum speed and hence maximum kinetic energy, while at the extreme position, the particle is momentarily at rest and hence its kinetic energy is minimum (zero).

The kinetic energy of a particle in SHM is given by the equation KE = 1/2 m v^2, where m is the mass of the particle and v is its velocity. The velocity in SHM is given by v = ω √(A^2 - x^2), where ω is the angular frequency, A is the amplitude, and x is the displacement from the mean position.

Substituting the expression for v into the KE equation gives KE = 1/2 m ω^2 (A^2 - x^2). This equation shows that the kinetic energy decreases from its maximum value of 1/2 m ω^2 A^2 at the mean position (x = 0) to zero at the extreme position (x = A).

So, the variation of kinetic energy with displacement in SHM is a decrease from maximum at the mean position to zero at the extreme position.

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In simple harmonic motion (SHM), the kinetic energy (KE) and potential energy (PE) of the particle are constantly interchanging. At the mean position, the particle has maximum speed and hence maximum kinetic energy, while at the extreme position, the particle is momentarily at rest and hence its kinetic energy is minimum (zero).

The kinetic energy of a particle in SHM is given by the equation KE = 1/2 m v^2, where m is the mass of the particle and v is its velocity. The velocity in SHM is given by v = ω √(A^2 - x^2), where ω is the angular frequency, A is the amplitude, and x is the displacement from the mean position.

Substituting the expression for v into the KE equation gives KE = 1/2 m ω^2 (A^2 - x^2). This equation shows that the kinetic energy decreases from its maximum value of 1/2 m ω^2 A^2 at the mean position (x = 0) to zero at the extreme position (x = A).

So, the variation of kinetic energy with displacement in SHM is a decrease from maximum at the mean position to zero at the extreme position.

Knowee AI · Accepted Answer

In simple harmonic motion (SHM), the kinetic energy (KE) and potential energy (PE) of the particle are constantly interchanging. At the mean position, the particle has maximum speed and hence maximum kinetic energy, while at the extreme position, the particle is momentarily at rest and hence its kinetic energy is minimum (zero).

The kinetic energy of a particle in SHM is given by the equation KE = 1/2 m v^2, where m is the mass of the particle and v is its velocity. The velocity in SHM is given by v = ω √(A^2 - x^2), where ω is the angular frequency, A is the amplitude, and x is the displacement from the mean position.

Substituting the expression for v into the KE equation gives KE = 1/2 m ω^2 (A^2 - x^2). This equation shows that the kinetic energy decreases from its maximum value of 1/2 m ω^2 A^2 at the mean position (x = 0) to zero at the extreme position (x = A).

So, the variation of kinetic energy with displacement in SHM is a decrease from maximum at the mean position to zero at the extreme position.

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x) starting from mean position to extreme position (A) is

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