The image shows a block of wood with height 2 cm, width 2 cm, and length 5 cm kept intwo different orientations on a table.How does the thrust and pressure applied by the block onto the table vary in these twoorientations?(a) Thrust of 50 N remains same, while pressure in orientation A is 5 N/ cm2 and inorientation B is 12.5 N/ cm2.(b) Thrust of 50 N remains same, while pressure in orientation A is 12.5 N/ cm2 and inorientation B is 5 N/ cm2.(c) Pressure of 50 N remains same, while thrust in orientation A is 5 N/ m2 and inorientation B is 12.5 N/ m2.(d) Pressure of 50 N remains same, while thrust in orientation A is 12.5 N/ m2 and inorientation B is 5 N/ m2
Question
The image shows a block of wood with height 2 cm, width 2 cm, and length 5 cm kept intwo different orientations on a table.How does the thrust and pressure applied by the block onto the table vary in these twoorientations?(a) Thrust of 50 N remains same, while pressure in orientation A is 5 N/ cm2 and inorientation B is 12.5 N/ cm2.(b) Thrust of 50 N remains same, while pressure in orientation A is 12.5 N/ cm2 and inorientation B is 5 N/ cm2.(c) Pressure of 50 N remains same, while thrust in orientation A is 5 N/ m2 and inorientation B is 12.5 N/ m2.(d) Pressure of 50 N remains same, while thrust in orientation A is 12.5 N/ m2 and inorientation B is 5 N/ m2
Solution
The answer to this question depends on the area of the block of wood that is in contact with the table in each orientation.
Thrust is the force exerted by an object on a surface in a direction perpendicular to the surface. In this case, the thrust is the weight of the block of wood, which is the same in both orientations.
Pressure is the force per unit area, or in this case, the thrust divided by the area of the block of wood that is in contact with the table.
In orientation A, if the block is standing on its end, the area in contact with the table is 2 cm * 2 cm = 4 cm^2. So the pressure is 50 N / 4 cm^2 = 12.5 N/cm^2.
In orientation B, if the block is lying flat, the area in contact with the table is 2 cm * 5 cm = 10 cm^2. So the pressure is 50 N / 10 cm^2 = 5 N/cm^2.
So the correct answer is (b) Thrust of 50 N remains same, while pressure in orientation A is 12.5 N/ cm^2 and in orientation B is 5 N/ cm^2.
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