A die is tossed twice. The probability of having a number greater than 4 on each toss isans.

Step 1: Understand the problem

A die has 6 faces, numbered from 1 to 6. When the problem says "a number greater than 4", it means either a 5 or a 6. So, there are 2 favorable outcomes out of 6 possible outcomes in a single toss.

Step 2: Calculate the probability for a single toss

The probability of a single event is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, the probability of getting a number greater than 4 in a single toss is 2/6 = 1/3.

Step 3: Calculate the probability for two tosses

The problem asks for the probability of this event happening twice in a row. When two events are independent (meaning the outcome of one does not affect the outcome of the other), the probability of both happening is the product of their individual probabilities.

So, the probability of getting a number greater than 4 on both tosses is (1/3) * (1/3) = 1/9.