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A new soft drink is being market tested. A sample of 400 individuals participated in the taste test and 80 indicated they like the taste. At a 5% significance level, test to determine if at least 22% of the population will like the new soft drink. conclusion for null hypothesis isGroup of answer choicesdo not reject H0revise horeject Ho

Question

A new soft drink is being market tested. A sample of 400 individuals participated in the taste test and 80 indicated they like the taste. At a 5% significance level, test to determine if at least 22% of the population will like the new soft drink. conclusion for null hypothesis isGroup of answer choicesdo not reject H0revise horeject Ho

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Solution

To answer this question, we need to perform a hypothesis test for a proportion. Here are the steps:

Step 1: State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: p = 0.22 (At least 22% of the population will like the new soft drink) Alternative hypothesis: p < 0.22 (Less than 22% of the population will like the new soft drink)

Step 2: Formulate an analysis plan. For this analysis, the significance level is defined as 0.05.

Step 3: Analyze sample data. Using sample data, we calculate the pooled sample proportion (p) and the standard error (SE). Using those measures, we compute the z-score test statistic (z).

p = 80 / 400 = 0.20 SE = sqrt{ [ p * ( 1 - p ) / n ] } = sqrt{ [ 0.20 * ( 1 - 0.20 ) / 400 ] } = 0.020 z = ( p - P ) / SE = ( 0.20 - 0.22 ) / 0.020 = -1.00

Step 4: Interpret the results. We use the Normal Distribution to find P(Z < -1.00) = 0.1587. Because the P-value (0.1587) is greater than the significance level (0.05), we cannot reject the null hypothesis.

Conclusion: Do not reject H0.

This problem has been solved

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