One gram of serum albumin in 1 dm3 of water gives a solution height of 3.9 mm when separated from pure water by a semi permeable membrane at 25°C. The molar mass of serum albumin is(density of solution 1.0 g cm-3; g = 9.81 ms-2)
Question
One gram of serum albumin in 1 dm3 of water gives a solution height of 3.9 mm when separated from pure water by a semi permeable membrane at 25°C. The molar mass of serum albumin is(density of solution 1.0 g cm-3; g = 9.81 ms-2)
Solution
It seems like you haven't provided a specific question related to the information given. However, I can help you understand how to calculate osmotic pressure based on the information provided.
The formula for osmotic pressure is:
Π = n/V * R * T
Where:
- Π is the osmotic pressure
- n is the number of moles of the solute
- V is the volume of the solution
- R is the ideal gas constant
- T is the temperature in Kelvin
From the information given, we can calculate the number of moles (n) of serum albumin in the solution using its molar mass.
1 gram of serum albumin is 1/molar mass moles of serum albumin.
The volume (V) of the solution is 1 dm^3 or 1 liter.
The temperature (T) is 25°C, which is 298.15 K in Kelvin.
The ideal gas constant (R) is 0.0821 Latm/(Kmol) or 8.3145 J/(K*mol) depending on the units you want for the osmotic pressure.
Substitute these values into the formula to find the osmotic pressure.
Please provide the molar mass of serum albumin and the specific question you want to answer for more detailed help.
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