In a 3-phase star connected system, VYN = 100∠−120° V and VBN = 100∠120° V. Then VYB will bea.Noneb.170∠90° Vc.200∠60° Vd.173∠− 90° V
Question
In a 3-phase star connected system, VYN = 100∠−120° V and VBN = 100∠120° V. Then VYB will bea.Noneb.170∠90° Vc.200∠60° Vd.173∠− 90° V
Solution
In a 3-phase star connected system, the line-to-line voltages can be calculated using the formula:
Vline-to-line = √3 * Vphase * ∠(phase angle ± 30°)
Given that VYN = 100∠−120° V and VBN = 100∠120° V, we can calculate VYB as follows:
VYB = VYN - VBN = 100∠−120° V - 100∠120° V = 100∠−120° V + 100∠-240° V (since subtracting a vector is the same as adding its negative) = 100∠−120° V + 100∠120° V (since 360° - 240° = 120°)
Adding these vectors together, we get:
VYB = 200∠0° V
However, this is not one of the options given. There may be a mistake in the question or the options provided.
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