Given a number n (greater than 9), write a code to find remainder when 'n' is divided by last two digits of n. If last two digits of the number are zero then print 'Division cannot be performed'.For example, if n is 314 then the output is 6 and when n is 12 output is 0. If n is 100 then print 'Division cannot be performed'Input FormatFirst line contains the number nOutput FormatPrint remainder of division of n by last two digits of n
Question
Given a number n (greater than 9), write a code to find remainder when 'n' is divided by last two digits of n. If last two digits of the number are zero then print 'Division cannot be performed'.For example, if n is 314 then the output is 6 and when n is 12 output is 0. If n is 100 then print 'Division cannot be performed'Input FormatFirst line contains the number nOutput FormatPrint remainder of division of n by last two digits of n
Solution
Here is a Python code that can solve the problem:
# Input the number
n = int(input())
# Extract the last two digits
last_two_digits = n % 100
# Check if the last two digits are zero
if last_two_digits == 0:
print('Division cannot be performed')
else:
# Calculate the remainder when n is divided by the last two digits
remainder = n % last_two_digits
print(remainder)
This code works by first taking an integer input n. It then calculates the last two digits of n by finding the remainder when n is divided by 100. If the last two digits are zero, it prints 'Division cannot be performed'. Otherwise, it calculates the remainder when n is divided by the last two digits and prints the result.
Similar Questions
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The remainder when the number 9999999925 is divided by 9 is
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