Design an algoritm and write a Java program with a class that read an integer ‘n’ as input and print the ‘n’ natural numbers in descending order sequence and their “Sum”. Print ‘invalid’ if the boundary conditions are not met.Boundary Condition: 0 < n > 1000Input Format:The first line contains an integer ‘n’Output Format:The first ‘n’ line contains the natural numbers in descending sequence or invalidThe ‘n+1’th line contains the Sum
Question
Design an algoritm and write a Java program with a class that read an integer ‘n’ as input and print the ‘n’ natural numbers in descending order sequence and their “Sum”. Print ‘invalid’ if the boundary conditions are not met.Boundary Condition: 0 < n > 1000Input Format:The first line contains an integer ‘n’Output Format:The first ‘n’ line contains the natural numbers in descending sequence or invalidThe ‘n+1’th line contains the Sum
Solution
Sure, here is a simple Java program that meets your requirements:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
if (n <= 0 || n > 1000) {
System.out.println("Invalid");
} else {
int sum = 0;
for (int i = n; i > 0; i--) {
System.out.println(i);
sum += i;
}
System.out.println("Sum: " + sum);
}
}
}
This program works as follows:
- It reads an integer
nfrom the input. - If
nis not in the range (0, 1000], it prints "Invalid". - Otherwise, it enters a loop that starts from
nand goes down to 1. - In each iteration of the loop, it prints the current number and adds it to the
sum. - After the loop, it prints the sum of the numbers.
Please note that this program assumes that the input is always a valid integer. If the input can be something else, you should add error handling code to deal with that.
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