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Given 2 numbers a and b, a%b represents the remainder when a is divided by b.For example, 12%5 = 2 because 12 when divided by 5 leaves a remainder of 2.Following are some rules of modulo arithmetic:(ab) % c = (ba) % c(a+b) % c = (b+a) % c(a*b) % c = (a%c * b%c)%c(ab * db) % c = (ad)b % c = (ad % c)b % cFind the largest possible number M such that 3452%M is equal to 1287%M.

Question

Given 2 numbers a and b, a%b represents the remainder when a is divided by b.For example, 12%5 = 2 because 12 when divided by 5 leaves a remainder of 2.Following are some rules of modulo arithmetic:(ab) % c = (ba) % c(a+b) % c = (b+a) % c(a*b) % c = (a%c * b%c)%c(ab * db) % c = (ad)b % c = (ad % c)b % cFind the largest possible number M such that 3452%M is equal to 1287%M.

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Solution 1

The problem is asking for the largest possible number M such that the remainder when 3452 is divided by M is the same as the remainder when 1287 is divided by M.

This is equivalent to saying that the difference between 3452 and 1287 is divisible by M.

So, we first calculate the difference between 3452 and 1287, which is 2165.

The largest possible number M that 2165 is divisible by is 2165 itself.

Therefore, the largest possible number M such that 3452%M is equal to 1287%M is 2165.

This problem has been solved

Solution 2

The problem is asking for the largest possible number M such that the remainder when 3452 is divided by M is the same as the remainder when 1287 is divided by M.

This is equivalent to saying that the difference between 3452 and 1287 is divisible by M.

So, we first calculate the difference between 3452 and 1287, which is 2165.

The largest possible number M that 2165 is divisible by is 2165 itself.

Therefore, the largest possible number M such that 3452%M is equal to 1287%M is 2165.

This problem has been solved

Solution 3

The problem is asking for the largest possible number M such that the remainder when 3452 is divided by M is the same as the remainder when 1287 is divided by M.

This is equivalent to finding the largest M such that 3452 and 1287 leave the same remainder when divided by M.

In other words, we are looking for the largest M such that 3452 - 1287 is divisible by M.

3452 - 1287 = 2165

The largest number that divides 2165 is 2165 itself.

Therefore, the largest possible number M is 2165.

This problem has been solved

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