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A) When a Li-ion battery is discharging, the electrode reactions are given as follows: (-) C6Li - xe = C6Li1-x + xLi+ (C6Li is Li-atom-intercalated, graphite-based composite) (+) Li1-xMO2 + xLi+ + xe = LiMO2 (M represents some kind of transitional metal) 1. ( ) During discharging, Li+ moves towards the negative electrode within the battery cell. 2. ( ) During charging, cathode reaction can be written as C6Li1-x + xLi+ + xe = C6Li. B) A MCFC is shown in the following figure, make judgements: 1. ( ) CH4 + H2O = CO + 3H2: one molar consumption of CH4 will cause transferring 12 mole electrons. 2. ( ) On electrode A, the reaction is H2 + 2OH- = 2H2O. 3. ( ) When the device is working, CO32- will move towards electrode B. 4. ( ) Reaction on electrode B is O2 + 2CO2 + 4e = 2CO32-

Question

A) When a Li-ion battery is discharging, the electrode reactions are given as follows:

(-) C6Li - xe = C6Li1-x + xLi+ (C6Li is Li-atom-intercalated, graphite-based composite)

(+) Li1-xMO2 + xLi+ + xe = LiMO2 (M represents some kind of transitional metal)

  1. ( ) During discharging, Li+ moves towards the negative electrode within the battery cell.
  2. ( ) During charging, cathode reaction can be written as C6Li1-x + xLi+ + xe = C6Li.

B) A MCFC is shown in the following figure, make judgements:

  1. ( ) CH4 + H2O = CO + 3H2: one molar consumption of CH4 will cause transferring 12 mole electrons.
  2. ( ) On electrode A, the reaction is H2 + 2OH- = 2H2O.
  3. ( ) When the device is working, CO32- will move towards electrode B.
  4. ( ) Reaction on electrode B is O2 + 2CO2 + 4e = 2CO32-
...expand
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Solution

A)

  1. (True) During discharging, Li+ ions move from the positive electrode to the negative electrode within the battery cell.
  2. (False) During charging, the cathode reaction is the reverse of the discharge reaction, which can be written as C6Li1-x - xLi+ - xe = C6Li.

B)

  1. (False) One molar consumption of CH4 will cause transferring 8 mole electrons, not 12. The reaction is CH4 + H2O = CO + 3H2, and each H2 can transfer 2 electrons, so total is 8 electrons.
  2. (True) On electrode A, the reaction is H2 + 2OH- = 2H2O + 2e-, which is an oxidation reaction.
  3. (True) When the device is working, CO32- ions will move towards electrode B.
  4. (True) Reaction on electrode B is O2 + 2CO2 + 4e- = 2CO32-, which is a reduction reaction.

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