Case study based questions:Read the following paragraph and answer the following questions:All chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced. All electrochemical cell reactions are also based on the mole concept. For example, a 4.0 molar aqueous solution of NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrodes. The amount of products formed can be calculated by using the mole [email protected] Switch account Draft saved* Indicates required questionEmail*Record [email protected] as the email to be included with my response(i) The total number of moles of chlorine gas evolved is*1 point(a) 0.5(b) 1.0(c) 1.5(d) 1.9(ii) If cathode is a Hg electrode, then the maximum weight of amalgam formed from this solution is*1 point(a) 300g(b) 446 g(c) 396 g(d) 256 g(iii) In the electrolytes, the number of moles of electrons involved are*1 point(a) 2(b) 1(c) 3(d) 4(iv) In electrolysis of aqueous NaCl solution when Pt electrode is taken, then which gas is liberated at cathode?*1 point(a) H2 gas(b) Cl2 gas(c) O2 gas(d) None of these(v) The total charge (coulomb) required for complete electrolysis is*1 point(a) 186000(b) 24125(c) 48296(d) 19300

(i) The total number of moles of chlorine gas evolved can be calculated using the formula: Molarity = Moles/Volume. Given that the molarity of the solution is 4.0 M and the volume is 500 mL or 0.5 L, we can rearrange the formula to find the moles: Moles = Molarity x Volume = 4.0 M x 0.5 L = 2.0 moles. However, the reaction of NaCl produces 1 mole of chlorine gas for every 2 moles of NaCl. Therefore, the total number of moles of chlorine gas evolved is 2.0 moles / 2 = 1.0 moles. So, the answer is (b) 1.0.

(ii) The maximum weight of amalgam formed from this solution cannot be determined without additional information about the specific reaction taking place at the cathode.

(iii) In the electrolysis of NaCl, 2 moles of electrons are involved for every mole of NaCl. This is because the reaction is 2NaCl -> 2Na + Cl2. Each Na atom loses one electron to become Na+, and each Cl2 molecule gains two electrons to become 2Cl-. So, the answer is (a) 2.

(iv) In the electrolysis of aqueous NaCl solution when Pt electrode is taken, H2 gas is liberated at the cathode. This is because water is reduced at the cathode to form H2 gas and OH- ions. So, the answer is (a) H2 gas.

(v) The total charge required for complete electrolysis can be calculated using Faraday's law of electrolysis, which states that the amount of substance produced at an electrode during electrolysis is directly proportional to the number of moles of electrons transferred at that electrode. The charge (in coulombs) is equal to the number of moles of electrons transferred times Faraday's constant (96485 C/mol). Given that 2 moles of electrons are transferred for every mole of NaCl and that there are 2.0 moles of NaCl, the total charge required is 2 moles e-/mole NaCl x 2.0 moles NaCl x 96485 C/mol e- = 386940 C. However, this is not one of the provided answer choices, so additional information or context may be needed to answer this question.