Question 10 of 10How much would $300 invested at 7% interest compounded continuously be worth after 4 years? Round your answer to the nearest cent.A.$396.93B.$384.00C.$306.53D.$347.09
Question
Question 10 of 10How much would 396.93B.306.53D.$347.09
Solution
To solve this problem, we can use the formula for continuous compound interest, which is A = P * e^(rt), where:
- A is the amount of money accumulated after n years, including interest.
- P is the principal amount (the initial amount of money).
- r is the annual interest rate (in decimal).
- t is the time the money is invested for in years.
Given in the problem: P = $300 r = 7% = 0.07 t = 4 years
Substitute these values into the formula:
A = 300 * e^(0.07*4)
Calculate the exponent first:
0.07 * 4 = 0.28
Then calculate e raised to this power:
e^0.28 ≈ 1.32313
Then multiply this by the principal amount:
300 * 1.32313 ≈ $396.94
So, the answer is approximately 396.93.
Similar Questions
How much would $500 invested at 4% interest compounded continuously be worth after 7 years? Round your answer to the nearest cent.𝐴(𝑡)=𝑃∙𝑒𝑟𝑡A(t)=P∙e rt A.$657.97B.$648.71C.$661.55D.$640.00SUBMITarrow_backPREVIOUS
Question 1 of 10How much would $200 invested at 5% interest compounded monthly be worth after 9 years? Round your answer to the nearest cent.A.$207.63B.$310.27C.$313.37D.$363.82
Question 8 of 10How much would $500 invested at 8% interest compounded annually be worth after 4 years? Round your answer to the nearest cent.A.$541.22B.$688.56C.$660.00D.$680.24
Question 9 of 10How much would $200 invested at 6% interest compounded annually be worth after 6 years? Round your answer to the nearest cent.A.$212.30B.$272.00C.$283.70D.$286.67
How much would $300 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cent.𝐴(𝑡)=𝑃∙𝑒𝑟𝑡A(t)=P∙e rt A.$392.98B.$381.00C.$364.18D.$306.11SUBMITarrow_backPREVIOUS
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.