Q. If a and ẞ be the zeroes of the polynomial ax² + bx + c, then the value of a Bis + Vβ να

To find the value of a Bis + Vβ να, we need to use the relationship between the zeroes of a quadratic polynomial and its coefficients.

Let's assume that a and ẞ are the zeroes of the polynomial ax² + bx + c. By Vieta's formulas, we know that the sum of the zeroes is equal to the negation of the coefficient of the linear term, and the product of the zeroes is equal to the constant term divided by the coefficient of the quadratic term.

So, we have the following equations:

a + ẞ = -b/a a * ẞ = c/a

To find the value of a Bis + Vβ να, we need to substitute the values of a and ẞ into the expression.

a Bis + Vβ να = a * (a + ẞ) + √(β * ν * α)

Substituting the values from the equations above, we get:

a Bis + Vβ να = a * (-b/a) + √(β * ν * α)

Simplifying the expression, we have:

a Bis + Vβ να = -b + √(β * ν * α)

Therefore, the value of a Bis + Vβ να is -b + √(β * ν * α).