25n 2 −24n+6=n

I'm sorry, but your question seems to be incomplete. Could you please provide the full equation?

The equation you've provided seems to have a typo. It's not clear what "25n 2" means. If you meant "25n^2", the equation would be a quadratic equation and could be solved as follows:

25n^2 - 24n + 6 = n

First, let's simplify the equation by subtracting n from both sides:

25n^2 - 25n + 6 = 0

Next, we can try to factor the quadratic equation. However, this equation does not factor nicely, so we'll have to use the quadratic formula instead. The quadratic formula is:

n = [-b ± sqrt(b^2 - 4ac)] / (2a)

In this equation, a = 25, b = -25, and c = 6. Plugging these values into the quadratic formula gives:

n = [25 ± sqrt((-25)^2 - 4256)] / (2*25) n = [25 ± sqrt(625 - 600)] / 50 n = [25 ± sqrt(25)] / 50 n = [25 ± 5] / 50

This gives us two solutions:

n = 30 / 50 = 0.6 n = 20 / 50 = 0.4

So, the solutions to the equation are n = 0.6 and n = 0.4.