a3q1.c: In function ‘main’:a3q1.c:21:12: warning: passing argument 1 of ‘printf’ from incompatible pointer type [-Wincompatible-pointer-types] 21 | printf(arr,n,k); | ^~~ | | | int *In file included from a3q1.c:1:/usr/include/stdio.h:332:43: note: expected ‘const char * restrict’ but argument is of type ‘int *’ 332 | extern int printf (const char *__restrict __format, ...); | ~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~
Question
a3q1.c: In function ‘main’:a3q1.c:21:12: warning: passing argument 1 of ‘printf’ from incompatible pointer type [-Wincompatible-pointer-types] 21 | printf(arr,n,k); | ^~~ | | | int *In file included from a3q1.c:1:/usr/include/stdio.h:332:43: note: expected ‘const char * restrict’ but argument is of type ‘int *’ 332 | extern int printf (const char *__restrict __format, ...); | ~~~~~~~~~~~~~~~~~^
Solution
The error message you're seeing is because you're trying to pass an integer pointer (int *) to the printf function, which expects a string (const char * restrict) as its first argument.
The printf function in C uses the first argument as a format string, which tells it how to format the remaining arguments.
Here's how you can fix this:
printf("%d %d", n, k);
In this case, "%d %d" is the format string. The %d is a placeholder that gets replaced with an integer. So this will print the values of n and k as integers.
If arr is an array of integers and you want to print its elements, you can use a loop:
for(int i = 0; i < size; i++) {
printf("%d ", arr[i]);
}
Replace size with the actual size of your array. This will print each element of the array followed by a space.
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